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思路：单调递增栈 + k 控制删除次数。高位越小整体越小，遇更小数字时弹出栈顶大数（仅当 k0）；栈空且当前为 0 则跳过（避免前导零）；若遍历完 k 仍0，从末尾再删 k 位。
lack of a compelling angle. Let's try IBM. IBM is such an important, famous
The mission has already faced years of delays, and Nasa is under pressure to get the astronauts on their way as soon as possible. However, the US space agency said it would not compromise on safety.